Economical apartment heating

Economical apartment heating

An example of calculating the heating of an apartment by infrared heaters.

Task:

Calculate the heat loss of a three-room apartment, the required number and power of infrared long-wave heaters, and electricity consumption per month.

1) Hall

 S – area 16 sq. m.

 h – ceiling height = 2.4m

One external wall, one large window - like two windows: + 10 W / sq.m one wall goes to the unheated room, which in turn goes into the staircase (unheated room): + 15 W / sq.m

Calculation: The average heat loss is taken as 100 W / sq. M

(100 W / sq. M + 10 W / sq.m + 15 W / sq.m) * 16 = 2000

Recommended: two infrared long-wave heaters model B1000 (possible option B600 - along the cold wall + B1000 - along the window with the expectation that the cold wall goes into the room).

Along the window, place one infrared long-wave heater B1000, and along the cold wall one infrared heater Teplov B1000

2) Kitchen

S – area of 8 sq. m.

 h – ceiling height = 2.4m

One outer wall, one window.

Calculation: The average heat loss is taken as 100 W / sq. M

100 W / sq. M * 8 = 800

Recommended:

Because the kitchen has its own additional heating, it is recommended that one infrared long-wave heater model B600

Along the window, place one Teplov B600 heater,

3) North bedroom

S – area of 9 sq. m.

h – ceiling height = 2.4m

One outer wall, one window.

Calculation: The average heat loss is taken as 100 W / sq. M

100 W / sq. M  * 9 =  900

Recommended by:

One infrared heater model B1000

Along the window, place one Teplov B1000 heater

4) South bedroom

S – area 11 sq m.

h – ceiling height = 2.4m

One cold wall opens onto a loggia that creates an air cushion:

- 20  W / sq.m

one window, but large with a balcony door + 10 W / sq.m (since the south room we add 10, not 20)

Calculation: The average heat loss is taken as 100 W / sq. M

(100 W / sq.m   -20 + 10 )* 11 =  99 

Recommended by:

Along the window, place one infrared long-wave heater Teplov B1000

5) Corridor

S – area 9 sq m.

h – ceiling height = 2.4m

one wall opens onto an unheated room. which in turn goes into the entrance (unheated room): + 15 W / sq.m

Calculation: The average heat loss is taken as 100 W / sq. M

(100 W / sq.m   -20 + 10 )*  =  99 

Recommended by:

There are no windows, this is an additional area, an additional heating is enough for it, then one infrared long-wave heater Teplov B600 is recommended

Along the front door, place one B600 heater